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Two mechanical waves, y(1) = 2 sin 2 pi ...

Two mechanical waves, `y_(1) = 2 sin 2 pi (5- t - 2x)` & `y_(2) = 4 sin 2 pi(fax + 100 t)` propagate in a medium with same speed.

A

The ratio of their intensities is `1 : 16`

B

The ratio of their intensities is `1 : 4`

C

The value of 'a' is `4` units

D

The value of 'a' is `2` units.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the two wave equations provided and find their properties, particularly the wave speed and the intensity ratio. ### Step-by-Step Solution: 1. **Identify the wave equations:** The given wave equations are: \[ y_1 = 2 \sin(2\pi(5 - t - 2x)) \] \[ y_2 = 4 \sin(2\pi(fax + 100t)) \] 2. **Rewrite the equations in standard form:** The standard form of a wave equation is: \[ y = A \sin(\omega t + kx) \quad \text{or} \quad y = A \sin(\omega t - kx) \] For \(y_1\): \[ y_1 = 2 \sin(2\pi(5 - t - 2x)) = 2 \sin(2\pi(5) - 2\pi t - 4\pi x) \] This can be simplified to: \[ y_1 = 2 \sin(-2\pi t - 4\pi x + 10\pi) \] Here, \(\omega_1 = 2\pi\) and \(k_1 = 4\pi\). For \(y_2\): \[ y_2 = 4 \sin(2\pi(fax + 100t)) = 4 \sin(2\pi(100t + fax)) \] Here, \(\omega_2 = 200\pi\) and \(k_2 = 2\pi f\). 3. **Calculate the wave speed for both waves:** The wave speed \(v\) is given by: \[ v = \frac{\omega}{k} \] For \(y_1\): \[ v_1 = \frac{2\pi}{4\pi} = \frac{1}{2} \text{ units} \] For \(y_2\): \[ v_2 = \frac{200\pi}{2\pi f} = \frac{100}{f} \text{ units} \] 4. **Set the wave speeds equal to each other:** Since both waves propagate at the same speed: \[ \frac{1}{2} = \frac{100}{f} \] Solving for \(f\): \[ f = 200 \text{ Hz} \] 5. **Calculate the intensity ratio:** The intensity \(I\) of a wave is proportional to the square of the amplitude and the square of the angular frequency: \[ I \propto A^2 \omega^2 \] For \(y_1\): \[ I_1 \propto (2^2)(2\pi)^2 = 4 \times 4\pi^2 = 16\pi^2 \] For \(y_2\): \[ I_2 \propto (4^2)(200\pi)^2 = 16 \times 40000\pi^2 = 640000\pi^2 \] 6. **Find the ratio of intensities:** \[ \frac{I_1}{I_2} = \frac{16\pi^2}{640000\pi^2} = \frac{16}{640000} = \frac{1}{40000} \] ### Final Results: - The frequency \(f\) is \(200 \text{ Hz}\). - The intensity ratio is \(1:40000\).

To solve the problem, we need to analyze the two wave equations provided and find their properties, particularly the wave speed and the intensity ratio. ### Step-by-Step Solution: 1. **Identify the wave equations:** The given wave equations are: \[ y_1 = 2 \sin(2\pi(5 - t - 2x)) ...
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