In an experiment to determine acceleration due to gravity, the length of the pendulum is measured as 98 cm be a scale of least count of 1 cm. The period of swing/oscillations is measured with the help of a stop watch having a least count of 1s. The time period of 50 oscillation is found to be 98 s. Express value of g with proper error limits.

Explanation

To solve the problem of determining the acceleration due to gravity (g) using a pendulum, we will follow these steps:

### Step 1: Calculate the Time Period of One Oscillation
The time period \( T \) for one oscillation can be calculated from the total time for 50 oscillations. Given that the time for 50 oscillations is 98 seconds:

\[ T = \frac{\text{Total Time}}{\text{Number of Oscillations}} = \frac{98 \, \text{s}}{50} = 1.96 \, \text{s} \]
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