The internal radius of a 1m long resonance tube is measured as 3.0 cm. A tuning fork of frequency 2000 Hz is used. The first resonating length is measured as 4.5 cm and the second resonating length is measured as 14.0 cm. We shall calculate the following.

Explanation

To solve the problem, we need to calculate the percentage error in the measurement of the effective length (E) of the resonance tube based on the given parameters. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Given Data
- Internal radius of the resonance tube (R) = 3.0 cm
- Length of the resonance tube (L) = 1 m = 100 cm
- Frequency of the tuning fork (f) = 2000 Hz
- First resonating length (L1) = 4.5 cm
- Second resonating length (L2) = 14.0 cm
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