Figure Shows a diode connected to an external resistance and an e.m.f. Assuming that the barrier potential developed in diode is `0.5 V`, obtain the value of current in the circuit in milliampere.

Explanation

`E = 45 V_(1) R = 100 Omega`
voltage drop across p-n junction = 0.5 V
effective voltage in the circuit `V = 4.5 - 0.5 = 4.0 V`
current in the circuit `I=(V)/(R)=(4.0)/(100)=0.04A=0.04xx1000mA=40mA`