The distance between two consecutive crests in a wave train produced in string is 5 m. If two complete waves pass through any point per second, the velocity of wave is :-

Options

A. 2.5 m/s
B. 5 m/s
C. 10 m/s
D. 15 m/s

Explanation

To solve the problem, we need to find the velocity of the wave using the given information about the wavelength and frequency. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Wavelength
The distance between two consecutive crests in a wave is defined as the wavelength (λ). According to the problem, the distance is given as:
\[ \lambda = 5 \, \text{m} \]

### Step 2: Identify the Frequency
The problem states that two complete waves pass through a point per second. This means the frequency (f) of the wave can be calculated as:
\[ f = 2 \, \text{waves/second} = 2 \, \text{Hz} \]

### Step 3: Use the Wave Velocity Formula
The velocity (v) of a wave can be calculated using the formula:
\[ v = f \cdot \lambda \]
Substituting the values we have:
\[ v = 2 \, \text{Hz} \times 5 \, \text{m} = 10 \, \text{m/s} \]

### Step 4: Conclusion
Thus, the velocity of the wave is:
\[ \text{Velocity of the wave} = 10 \, \text{m/s} \]