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Two open pipes of length L are vibrated ...

Two open pipes of length L are vibrated simultaneously. If length of one of the pipes is reduced by y. then the number of beats heats per second will be if the velocity of sound is v and `y lt lt L` :-

A

`(vy)/(2L^(2))`

B

`(vy)/(L^(2))`

C

`(vy)/(2L)`

D

`(2L^(2))/(vy)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these procedures: ### Step 1: Understand the Problem We have two open pipes of length \( L \) that are producing sound simultaneously. One of the pipes has its length reduced by \( y \). We need to find the number of beats per second produced by the two pipes when they vibrate. ### Step 2: Determine the Frequencies of the Pipes The frequency of a pipe is given by the formula: \[ f = \frac{v}{\lambda} \] where \( v \) is the speed of sound and \( \lambda \) is the wavelength. For the first pipe (length \( L \)): - The wavelength \( \lambda_1 \) is given by: \[ \lambda_1 = 2L \quad \text{(since it is an open pipe)} \] Thus, the frequency \( f_1 \) is: \[ f_1 = \frac{v}{\lambda_1} = \frac{v}{2L} \] For the second pipe (length \( L - y \)): - The wavelength \( \lambda_2 \) is given by: \[ \lambda_2 = 2(L - y) \] Thus, the frequency \( f_2 \) is: \[ f_2 = \frac{v}{\lambda_2} = \frac{v}{2(L - y)} \] ### Step 3: Calculate the Beat Frequency The number of beats per second is given by the absolute difference between the two frequencies: \[ \text{Beats per second} = |f_2 - f_1| \] Substituting the frequencies we found: \[ \text{Beats per second} = \left| \frac{v}{2(L - y)} - \frac{v}{2L} \right| \] ### Step 4: Simplify the Expression Factoring out \( \frac{v}{2} \): \[ \text{Beats per second} = \frac{v}{2} \left| \frac{1}{L - y} - \frac{1}{L} \right| \] Finding a common denominator: \[ \text{Beats per second} = \frac{v}{2} \left| \frac{L - (L - y)}{L(L - y)} \right| = \frac{v}{2} \left| \frac{y}{L(L - y)} \right| \] Since \( y \ll L \), we can approximate \( L - y \approx L \): \[ \text{Beats per second} \approx \frac{v}{2} \cdot \frac{y}{L^2} \] ### Step 5: Final Result Thus, the number of beats per second is: \[ \text{Beats per second} = \frac{v y}{2 L^2} \]

To solve the problem step by step, we will follow these procedures: ### Step 1: Understand the Problem We have two open pipes of length \( L \) that are producing sound simultaneously. One of the pipes has its length reduced by \( y \). We need to find the number of beats per second produced by the two pipes when they vibrate. ### Step 2: Determine the Frequencies of the Pipes The frequency of a pipe is given by the formula: \[ ...
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