Two tuning forks with natural frequencies 340 Hz each move relative to a stationary observer. One fork moves away from the observer, while the other moves towards the observer at the same speed. The observer hears beats of frequency 3 Hz. Find the speed of the tuning forks (speed of sound is `340(m)/(s)`).

Answer

`1.5 m//s`

Explanation

`Delta f=f_(0)((v)/(v-v_(S)))-f_(0)((v)/(v+v_(S)))=3`
`rArr 3=340[(330)/(330-V_(S))-(330)/(330+V_(S))]rArr V_(S)=1.5m//s`