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When a copper sphere is heated, percenta...

When a copper sphere is heated, percentage change is

A

radius

B

area

C

volume

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Area (A) = `4 piR^(2)`, Volume `(V)=(4)/(3)piR^(3)`
`(DeltaA)/(A)=2(DeltaR)/(R),(DeltaV)/(V)=3(DeltaR)/(R)`
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