A Ge specimen is doped with Al. The concentration of electron - hole pair at this temperature is `~10^(19)m^(-3)`, the concentration of electrons in the specimen is :

Options

A. `10^(17)//m^(3)`
B. `10^(15)//m^(3)`
C. `10^(4)//m^(3)`
D. `10^(2)//m^(3)`

Answer

A

Explanation

`n_(e)=(n_(i)^(2))/(n_(h))=((10^(19))^(2))/(10^(23))=10^(17)m^(-3)`