For a common base configuration of `PNP` transistor `(l_(C))/(l_(E))=0.98`, then maximum current gain in common emitter configuration will be

Options

A. 49
B. 98
C. 4.9
D. `24`

Explanation

To solve the problem, we need to find the maximum current gain in the common emitter configuration of a PNP transistor given that the ratio of collector current to emitter current in the common base configuration is \( \frac{I_C}{I_E} = 0.98 \).

### Step-by-Step Solution:

1. **Understand the Definitions**:
- In the common base configuration, the current gain is denoted by \( \alpha \), which is defined as:
\[ \alpha = \frac{I_C}{I_E} \]
- In the common emitter configuration, the current gain is denoted by \( \beta \), which is defined as:
\[ \beta = \frac{I_C}{I_B} \]
- There is a relationship between \( \alpha \) and \( \beta \):
\[ \beta = \frac{\alpha}{1 - \alpha} \]

2. **Substitute the Given Value**:
- From the problem, we have \( \alpha = 0.98 \).
- We can now substitute this value into the formula for \( \beta \):
\[ \beta = \frac{0.98}{1 - 0.98} \]

3. **Calculate the Denominator**:
- Calculate \( 1 - 0.98 \):
\[ 1 - 0.98 = 0.02 \]

4. **Calculate \( \beta \)**:
- Now substitute the value of the denominator back into the equation for \( \beta \):
\[ \beta = \frac{0.98}{0.02} \]

5. **Perform the Division**:
- To simplify \( \frac{0.98}{0.02} \):
\[ \beta = \frac{98}{2} = 49 \]

6. **Conclusion**:
- The maximum current gain in the common emitter configuration is:
\[ \beta = 49 \]

### Final Answer:
The maximum current gain in the common emitter configuration of the PNP transistor is **49**.