When all the inputs of a NAND gate are connected together, the resulting circuit is :-

Options

A. a NOT gate
B. an AND gate
C. an OR gate
D. a NOR gate

Answer

To solve the question, we need to analyze the behavior of a NAND gate when all its inputs are connected together. Let's break it down step by step.

### Step-by-Step Solution:

1. **Understanding the NAND Gate**:
The NAND gate is a digital logic gate that outputs false only when all its inputs are true. The logic expression for a NAND gate with two inputs A and B is given by:
\[ Y = \overline{A \cdot B} \]
where \( \overline{} \) denotes the NOT operation.

2. **Connecting Inputs Together**:
When all inputs of the NAND gate are connected together, let's denote this common input as A. In this case, both inputs of the NAND gate can be considered equal:
\[ A = B = C = ... = A \]

3. **Substituting the Inputs**:
Now, substituting the inputs into the NAND gate equation, we have:
\[ Y = \overline{A \cdot A} \]
This simplifies to:
\[ Y = \overline{A^2} \]
Since \( A^2 = A \) (in Boolean algebra), we can further simplify this to:
\[ Y = \overline{A} \]

4. **Identifying the Resulting Circuit**:
The expression \( Y = \overline{A} \) is the characteristic equation of a NOT gate. Therefore, when all inputs of a NAND gate are connected together, the resulting circuit behaves like a NOT gate.

5. **Conclusion**:
Based on our analysis, the correct answer to the question is that the resulting circuit is a NOT gate.

### Final Answer:
The resulting circuit is a NOT gate.