The current of transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in the base current by `5.0 muA`m will be :-

Options

A. `245 muA,250 muA`
B. `240 muA,235 muA`
C. `260 muA,255 muA`
D. None of these

Explanation

To solve the problem, we need to find the change in collector current (ΔIc) and the change in emitter current (ΔIe) given the change in base current (ΔIb) and the current gain (β) of the transistor in common emitter mode.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Change in base current (ΔIb) = 5.0 μA
- Current gain (β) = 49

2. **Calculate Change in Collector Current (ΔIc):**
- The relationship between the change in collector current and the change in base current is given by the formula:
\[ ΔIc = β \times ΔIb \]
- Substituting the known values:
\[ ΔIc = 49 \times 5.0 \, μA \]
- Performing the multiplication:
\[ ΔIc = 245 \, μA \]

3. **Calculate Change in Emitter Current (ΔIe):**
- The change in emitter current is related to the changes in base and collector currents by the formula:
\[ ΔIe = ΔIb + ΔIc \]
- Substituting the values we have:
\[ ΔIe = 5.0 \, μA + 245 \, μA \]
- Performing the addition:
\[ ΔIe = 250 \, μA \]

4. **Final Results:**
- Change in collector current (ΔIc) = 245 μA
- Change in emitter current (ΔIe) = 250 μA

### Summary of the Results:
- ΔIc = 245 μA
- ΔIe = 250 μA