Statement-I : For the same antenna length, power radiated by short wavelength signals would be large.
Statement-II : Because power radiated `prop (1)/(lamda^(2))`

Options

A. Statetment-I is True, Statement-II is True , Statement-II is a correct explanation for Statement-I
B. Statement-I is True, Statement-II is True , Statement-II is NOT a correct explanation for Statement-I
C. Statement-I is True, Statement-II is False
D. Statement-I is False, Statement-II is True

Answer

To solve the question, we need to analyze both statements provided and determine their validity and relationship.

### Step-by-Step Solution:

1. **Understanding Statement-I**:
- Statement-I claims that for the same antenna length, the power radiated by short wavelength signals would be large.
- This implies that shorter wavelengths lead to higher power radiation.

2. **Understanding Statement-II**:
- Statement-II states that the power radiated is inversely proportional to the square of the wavelength (λ). Mathematically, this can be expressed as:
\[ P \propto \frac{1}{\lambda^2} \]
- This means that as the wavelength (λ) decreases (shorter wavelengths), the power (P) radiated increases.

3. **Analyzing the Relationship**:
- From Statement-II, we can conclude that if the wavelength is short (small λ), the power radiated (P) will indeed be large.
- Conversely, if the wavelength is long (large λ), the power radiated will be small.

4. **Conclusion**:
- Since Statement-I is true (short wavelengths lead to higher power) and Statement-II provides the correct explanation for Statement-I (power is inversely proportional to the square of the wavelength), we can conclude that both statements are true.
- Therefore, Statement-II correctly explains Statement-I.

5. **Final Answer**:
- Both Statement-I and Statement-II are true, and Statement-II is the correct explanation for Statement-I. Thus, the answer is option A.