The area of cross-section of the two vertical arms of hydraulic press are `1 cm^(2)` and `10 cm^(2)` respectively. A force of 10 N applied as shown in the figure to a light piston in the thinner arm balances a force F applied to the corresponding piston in the thicker arm. Assuming that the levels of water in both the arms are the same, we can conclude that,

Options

A. F=100N
B. F=50N
C. F=25N
D. F, as applied, cannot balance the effect of the force on the first piston

Answer

B

Explanation

`(10xx cos 60^(@))/(1)=(F)/(10)rArrF=50N`