The velocity vector at a point A varies with time as `vecv=ahati+bthatj` , where a and b are positive constants. The equation of trajectory of the point would be

Options

A. `a^(2)+bx^(2)=0`
B. `a^(2)y=bx^(2)`
C. `y=(b)/(a^(2))x`
D. `ay^(2)=b^(2)x`

Answer

B

Explanation

`x=at,y=bt^(2),t=(x)/(a),`
`thereforey=b((x)/(a))^(2)rArra^(2)y=bx^(2)`