Assertion:- Two stones are simultaneously projected from level ground from same point with same speeds but different angles with horizontal Both stones move in same vertical plane. Then the two stones may collide in mid air.
Reason:- `For two stones projected simultaneously from same point with same speed at different angles with horizontal, their trajectories must intersect at some point except projection point.

Options

A. If both Assertion `&` Reason are True `&` the Reason is a correct explanation of the Assertion.
B. If both Assertion `&` Reason are True but Reason is not a correct explanation of the Assertion.
C. If Assertion is True but the Reason is False.
D. If both Assertion `&` Reason are False.

Answer

To solve the question, we need to analyze the assertion and the reason provided.

**Assertion:** Two stones are simultaneously projected from level ground from the same point with the same speeds but different angles with the horizontal. Both stones move in the same vertical plane. Then the two stones may collide in mid-air.

**Reason:** For two stones projected simultaneously from the same point with the same speed at different angles with the horizontal, their trajectories must intersect at some point except the projection point.

### Step-by-Step Solution:

1. **Understanding Projectile Motion:**
- When two stones are projected from the same point with the same speed but at different angles, they will follow parabolic trajectories. The motion can be analyzed by breaking it down into horizontal and vertical components.

2. **Horizontal and Vertical Components:**
- For stone 1 projected at angle \( \theta_1 \):
- Horizontal component of velocity: \( u \cos \theta_1 \)
- Vertical component of velocity: \( u \sin \theta_1 \)
- For stone 2 projected at angle \( \theta_2 \):
- Horizontal component of velocity: \( u \cos \theta_2 \)
- Vertical component of velocity: \( u \sin \theta_2 \)

3. **Displacement Equations:**
- The horizontal displacement \( S_{x1} \) of stone 1 at time \( t \) is given by:
\[ S_{x1} = u \cos \theta_1 \cdot t \]
- The horizontal displacement \( S_{x2} \) of stone 2 at the same time \( t \) is given by:
\[ S_{x2} = u \cos \theta_2 \cdot t \]

4. **Condition for Collision:**
- For the two stones to collide, their horizontal displacements must be equal at the same time:
\[ S_{x1} = S_{x2} \implies u \cos \theta_1 \cdot t = u \cos \theta_2 \cdot t \]
- Since \( \theta_1 \neq \theta_2 \), it follows that \( \cos \theta_1 \neq \cos \theta_2 \), which implies that \( S_{x1} \) will not equal \( S_{x2} \) for any \( t \).

5. **Conclusion on Assertion:**
- Therefore, the assertion that the two stones may collide in mid-air is **false**.

6. **Analyzing the Reason:**
- The reason states that the trajectories must intersect at some point except the projection point. However, as shown, the trajectories of the two stones do not necessarily intersect because they travel different horizontal distances due to their different angles.
- Thus, the reason is also **false**.

### Final Answer:
Both the assertion and the reason are false.