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Let B(P) and B(Q) be the magnetic field ...

Let `B_(P)` and `B_(Q)` be the magnetic field produced by the wire `P` and `Q` which are placed symmetrically in a rectangular loop `ABCD` as shown in figure.Current in wire `P` is `I` directed inward and in `Q` is `2I` directed outwards.if `underset(A)overset(B)intvecB_(Q).vecdl=2mu_(0)` tesla meter,`underset(D)overset(A)intvecB_(P).vecdl=-2mu_(0)` tesla meter,&`underset(A)overset(B)intvecB_(P).vecdl=-mu_(0)` tesla meter tesla meter the value of `I` will be:

A

8A

B

4A

C

5A

D

6A

Text Solution

Verified by Experts

The correct Answer is:
D
`(2mu_(0)-mu_(0))+(-mu_(0)+2mu_(0))+(-2mu_(0)+4mu_(0))+(4mu_(0)-2mu_(0))=mu_(0)IrArrI=6A`
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