If magnetic field in space is `1Thati`, electric field is `10 N//Chati`, no gravitational field is present and a charged particle is released from rest from origin, it will

Options

A. not move at all
B. move in circular path
C. move in a helical path
D. move on a straight line

Explanation

To solve the problem, we need to analyze the forces acting on a charged particle released from rest in the presence of electric and magnetic fields.

### Step-by-Step Solution:

1. **Identify the Given Information**:
- Magnetic field, \( \vec{B} = 1 \, \text{Tesla} \) in the direction of \( \hat{i} \).
- Electric field, \( \vec{E} = 10 \, \text{N/C} \) in the direction of \( \hat{i} \).
- The particle is released from rest at the origin.

2. **Determine the Forces Acting on the Charged Particle**:
- The force due to the electric field on a charge \( Q \) is given by:
\[ \vec{F_E} = Q \vec{E} = Q \cdot 10 \, \hat{i} = 10Q \, \hat{i} \]
- The magnetic force on a charge moving with velocity \( \vec{V} \) in a magnetic field \( \vec{B} \) is given by:
\[ \vec{F_B} = Q (\vec{V} \times \vec{B}) \]
- Since the particle is released from rest, its initial velocity \( \vec{V} = 0 \). Therefore, the magnetic force is:
\[ \vec{F_B} = Q (0 \times \vec{B}) = 0 \]

3. **Analyze the Motion of the Charged Particle**:
- The only force acting on the charged particle is the electric force \( \vec{F_E} = 10Q \, \hat{i} \).
- Since there is no magnetic force acting on the particle (as it is at rest), the particle will start to accelerate in the direction of the electric field.

4. **Conclusion**:
- The charged particle will move in the direction of the electric field (along \( \hat{i} \)) with an increasing velocity due to the constant electric force acting on it.
- Since there is no magnetic force acting on it, it will continue to move in a straight line.

### Final Answer:
The charged particle will move in a straight line along the direction of the electric field.