If uncertainty principle is applied to an object of mass 1 milligram, the uncertainty value of velocity and position will be

Options

A. `10^(-4) m^(2)s^(-1)`
B. `10^(6)m^(2)s^(-1)`
C. `5xx10^(-29)m^(2)s^(-1)`
D. `10^(-34)m^(2)s^(-1)`

Answer

C

Explanation

`Deltax x mx Deltav=(h)/(4pi)`
`Deltax Deltav=(h)/(2 pi xx m)=(6.62xx10^(-34))/(4xx3.14xx10^(-6))=5.44xx10^(-29)m^(2)s^(-1)`