Two particles of masses 2 kg and 3 kg are moving under their mutual interaction in free space. At an instant they were observed at points(-2m,1m,4m) and(2m,-3m,6m) with velocities `(3hati-2hatj+hatk)m//s " and " (-hati+hatj-2hatk)m//s` respectively. If after 10 sec, the first particle passes the point (6m,8m,-6m), find coordinate of the point where the second particle at this instant?

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Identify the Initial Conditions
We have two particles with the following properties:
- Particle 1 (mass \( m_1 = 2 \, \text{kg} \)):
- Initial position: \( \mathbf{r_1} = (-2 \, \text{m}, 1 \, \text{m}, 4 \, \text{m}) \)
- Velocity: \( \mathbf{v_1} = (3 \hat{i} - 2 \hat{j} + \hat{k}) \, \text{m/s} \)

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