A particle of mass 2kg is moving in free space with velocity `vecv_0=(2hati-3hatj+hatk)m//s` is acted upon by force `vecF=(2hati+hatj-2hatk)N`. Find velocity vector of the particle 3s after the force starts acting.

Explanation

To find the velocity vector of the particle 3 seconds after the force starts acting, we can follow these steps:

### Step 1: Identify the Given Values
- Mass of the particle, \( m = 2 \, \text{kg} \)
- Initial velocity vector, \( \vec{v_0} = 2 \hat{i} - 3 \hat{j} + \hat{k} \, \text{m/s} \)
- Force vector, \( \vec{F} = 2 \hat{i} + \hat{j} - 2 \hat{k} \, \text{N} \)
- Time duration, \( \Delta t = 3 \, \text{s} \)

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