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Two block A and B of masses m and `2m` respectively are connected by a spring of spring cosntant k. The masses are moving to the right with a uniform velocity `v_(0)` each, the heavier mass leading the lighter one. The spring is of natural length during this motion. Block B collides head on with a thrid block C of mass `2m`. at rest, the collision being completely inelastic.

The velocity of block B just after collision is -

A

`v_(0)`

B

`(v_(0))/(2)`

C

`(3v_(0))/(5)`

D

`(2v_(0))/(5)`

Text Solution

Verified by Experts

The correct Answer is:
(B)
by applying conservation of linear momentum `2mv_(0) = (2m + 2m)v rArr v = (v_(0))/(2)`
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