A circular plate of uniform thickness has a diameter fo 56cm. A circular portion of diameter 42 cm is removed from one edge of the plate as shown in figure. Find the position of the centre of mass of the remaining portion.

Answer

`9 cm` from centre of bigger circle (leftwards)

Explanation

`x_(cm) = ((rho(pi xx 56^(2))/(4)) xx 28 + (rho(pi xx 42^(2))/(4)) xx 35)/((rho(pi xx 56^(2))/(4)) - (rho(pi xx 42^(2))/(4)))`
`= 9 cm` from left edge