A hemisphere of radius R and mass 4 m is free to slide with its base on a smooth horizontal table . A particle of mass m is placed on the top of the hemisphere . The angular velocity of the particle relative to centre of hemisphere at an angular displacement `theta` when velocity of hemisphere has become v is

Answer

`(5v)/(R cos theta)`

Explanation

Let `v =` velocity of wege and `u =` velocity of particle relative to wedge

COLM
`rArr m (v + u cos theta) + 4 mv = 0`
`rArr u cos theta = -5v, omega = (u)/(R ) = (5v)/(R cos theta)`