A small sphere of radius R is held against the inner surface of larger sphere of radius `6R` (as shown in figure). The masses of large and small spheres are `4M` and M respectively. This arrangement is placed on a horizontal table. There is no friction between any surfaces of contact. The small sphere is now released. Find the coordinates of the centre of the large spheres, when the smaller sphere reaches the other extreme position.

Answer

`(L + 2R, 0)`

Explanation

`x_(cm) = (4 ML + M(L + 5R))/(5M) = (4MX + M(X - 5R))/(5M)`
`rArr x = L + 2R`