The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

Options

A. `sqrtMk L`
B. `(kL^(2))/(2M)`
C. zero
D. `(ML^(2))/(k)`

Answer

A

Explanation

Let maximum momentum be p then
`(p^(2))/(2M) = (1)/(2) kL^(2) rArr p = L sqrt(Mk)`