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Let N=alphaalphaalphaalphaalphaalpha be ...

Let` N=alphaalphaalphaalphaalphaalpha` be a 6 digit number (all digit repeated) and N is divisible by 924 and let `alpha,beta` the roots of the equation `x^(2)-11x+lambda=0`, if product of all possible values of `lambda` is `168K` then the value of K is

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The correct Answer is:
D
`N = alpha (111111)` is divisible by `7xx11xx3`.
Hence for N to be a divisible by 924, `alpha=4` or 8
and `alpha` and `beta` are roots of `x^(2)-11x+lambda=0`
`impliesalpha+beta=11`
`implies (alpha,beta)-=(4,7),(8,3)`
possible value of lambda =28,24
implies product of `lambda =672`
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