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The most important copper oxide containi...

The most important copper oxide containing minerals are azurite `{Cu_(3)(OH)_(2)(CO_(3))_(2)}`, malachite `{Cu_(2)(OH)_(2)(CO_(3))}`, cuprite `(Cu_(2)O)`, tenorite `(CuO)`. Extraction of copper from these low grade ores involves leaching followed by reduction.
Some `Cu` is obtained just on leaching by dil `H_(2)SO_(4)` in :

A

Malachite

B

Tenorite

C

Cuprite

D

Azurite

Text Solution

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The correct Answer is:
To solve the problem, we need to determine which of the given copper oxide minerals can yield copper when leached with dilute sulfuric acid (H₂SO₄). The minerals in question are azurite, malachite, cuprite, and tenorite. ### Step-by-Step Solution: 1. **Identify the Minerals and Their Formulas**: - Azurite: \( \text{Cu}_3(\text{OH})_2(\text{CO}_3)_2 \) - Malachite: \( \text{Cu}_2(\text{OH})_2(\text{CO}_3) \) - Cuprite: \( \text{Cu}_2\text{O} \) - Tenorite: \( \text{CuO} \) 2. **Reactions with Dilute H₂SO₄**: - **Azurite Reaction**: \[ \text{Cu}_3(\text{OH})_2(\text{CO}_3)_2 + 6 \text{H}_2\text{SO}_4 \rightarrow 3 \text{CuSO}_4 + 2 \text{CO}_2 + 4 \text{H}_2\text{O} \] - Here, copper sulfate is produced, but no elemental copper is obtained. - **Malachite Reaction**: \[ \text{Cu}_2(\text{OH})_2(\text{CO}_3) + 2 \text{H}_2\text{SO}_4 \rightarrow 2 \text{CuSO}_4 + \text{CO}_2 + 2 \text{H}_2\text{O} \] - Similar to azurite, copper sulfate is produced without any elemental copper. - **Cuprite Reaction**: \[ \text{Cu}_2\text{O} + 2 \text{H}_2\text{SO}_4 \rightarrow 2 \text{Cu} + \text{CuSO}_4 + 2 \text{H}_2\text{O} \] - In this case, elemental copper is produced, indicating that cuprite can yield copper when leached with dilute H₂SO₄. - **Tenorite Reaction**: \[ \text{CuO} + \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} \] - Again, only copper sulfate is produced, with no elemental copper. 3. **Conclusion**: - From the reactions, we see that only cuprite (\( \text{Cu}_2\text{O} \)) produces elemental copper when reacted with dilute sulfuric acid. Therefore, the answer is **cuprite**. ### Final Answer: The mineral from which copper can be obtained just on leaching with dilute H₂SO₄ is **cuprite**.
To solve the problem, we need to determine which of the given copper oxide minerals can yield copper when leached with dilute sulfuric acid (H₂SO₄). The minerals in question are azurite, malachite, cuprite, and tenorite. ### Step-by-Step Solution: 1. **Identify the Minerals and Their Formulas**: - Azurite: \( \text{Cu}_3(\text{OH})_2(\text{CO}_3)_2 \) - Malachite: \( \text{Cu}_2(\text{OH})_2(\text{CO}_3) \) - Cuprite: \( \text{Cu}_2\text{O} \) ...
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