Match the pairs of compounds (to be distinguished) given in Column-(I) with the appropriate reagents given in Column-II
`{:(,"Column-I",,"Column-II",),((A),CH_(3)-CH_(2)-CHO & "acetone",(P),"Ammoniacal" Cu_(2)Cl(2)"solution",),((B),CH_(3)-CH_(2)-CHO & "bezaldehyde",(Q),"Ammoniacal" AgNO_(3) "solution",),((C),CH_(3)-CH_(2)-C-=CH&CH_(3)-C-=C-CH_(3),(R),Br_(2) "in"C Cl_(4),),((D),CH_(3)-C-=CH &"propane",(S),"Fehling solution",),(,,(T),"Iodoform test",):}`

Answer

To solve the problem of matching the pairs of compounds from Column-I with the appropriate reagents from Column-II, we can follow these steps:

### Step 1: Identify the Compounds in Column-I
- **(A)** CH₃-CH₂-CHO (Propanal) & Acetone (CH₃-CO-CH₃)
- **(B)** CH₃-CH₂-CHO (Propanal) & Benzaldehyde (C₆H₅-CHO)
- **(C)** CH₃-CH₂-C≡C-CH₃ (Butyne) & CH₃-C≡C-CH₃ (Butyne)
- **(D)** CH₃-C≡C-H (Propyne) & Propane (CH₃-CH₂-CH₃)

### Step 2: Identify the Reagents in Column-II
- **(P)** Ammoniacal Cu₂Cl₂ solution
- **(Q)** Ammoniacal AgNO₃ solution (Tollens' reagent)
- **(R)** Br₂ in CCl₄
- **(S)** Fehling solution
- **(T)** Iodoform test

### Step 3: Match the Compounds with the Reagents
1. **For Pair (A)**:
- **Propanal (Aldehyde)** and **Acetone (Ketone)** can be distinguished using **Tollens' reagent (Q)** and **Fehling solution (S)**.
- **Acetone** will not react with these reagents, while **Propanal** will give a positive test.
- **Iodoform test (T)** can also be used since acetone is a methylated carbonyl compound.
- **Match**: A → Q, S, T

2. **For Pair (B)**:
- **Propanal (Aldehyde)** and **Benzaldehyde (Aromatic Aldehyde)** can be distinguished using **Fehling solution (S)**.
- **Propanal** gives a positive test, while **Benzaldehyde** gives a negative test.
- **Match**: B → S

3. **For Pair (C)**:
- **Terminal Alkyne (Butyne)** can be distinguished using **Tollens' reagent (Q)** and **Ammoniacal Cu₂Cl₂ solution (P)**, as terminal alkynes give a positive test.
- **Match**: C → P, Q

4. **For Pair (D)**:
- **Propyne (Terminal Alkyne)** and **Propane (Saturated Hydrocarbon)** can be distinguished using **Br₂ in CCl₄ (R)**, which will decolorize in the presence of unsaturation (in Propyne).
- **Match**: D → R

### Final Matches:
- A → Q, S, T
- B → S
- C → P, Q
- D → R