Match the following:
`{:("Coloumn-I",,"Column-II"),("(Aqueous solution in standard condition)",,"(Product of electrolysis using inert electrode)"),((A)"KCl",,(P)"Metal discharged at cathode"),((B)H_(2)SO_(4),,(Q)H_(2) "discharged"),((C)CuSO_(4),,(R )O_(2)"discharged" ),((D)NaNO_(3),,(S)"Non- metal discharged at both electrodes"),(,,(T)"Net cell reaction is" :2H_(2)OrarrO_(2)+2H_(2) ):}`

Answer

To solve the matching question, we will analyze each aqueous solution from Column I and determine the corresponding product of electrolysis from Column II.

### Step-by-Step Solution:

1. **Identify the Electrolysis Products for KCl:**
- **Aqueous Solution:** KCl dissociates into K⁺ and Cl⁻ ions.
- **At Cathode:** H₂ is discharged because K⁺ has a higher reduction potential than H⁺.
- **At Anode:** Cl₂ is produced because Cl⁻ is discharged.
- **Match:** KCl (A) → H₂ discharged (Q).

2. **Identify the Electrolysis Products for H₂SO₄:**
- **Aqueous Solution:** H₂SO₄ dissociates into H⁺ and SO₄²⁻ ions.
- **At Cathode:** H₂ is discharged from H⁺ ions.
- **At Anode:** O₂ is produced because SO₄²⁻ has a higher oxidation potential than OH⁻.
- **Match:** H₂SO₄ (B) → H₂ discharged (Q) and O₂ discharged (R).

3. **Identify the Electrolysis Products for CuSO₄:**
- **Aqueous Solution:** CuSO₄ dissociates into Cu²⁺ and SO₄²⁻ ions.
- **At Cathode:** Cu is deposited because Cu²⁺ is discharged (it is less than H⁺).
- **At Anode:** O₂ is produced from the oxidation of OH⁻.
- **Match:** CuSO₄ (C) → Metal discharged at cathode (P) and O₂ discharged (R).

4. **Identify the Electrolysis Products for NaNO₃:**
- **Aqueous Solution:** NaNO₃ dissociates into Na⁺ and NO₃⁻ ions.
- **At Cathode:** H₂ is discharged because Na⁺ has a higher reduction potential than H⁺.
- **At Anode:** O₂ is produced because NO₃⁻ has a higher oxidation potential than OH⁻.
- **Match:** NaNO₃ (D) → H₂ discharged (Q) and O₂ discharged (R).

5. **Net Cell Reaction:**
- The overall reaction for the electrolysis of water can be represented as:
\[ 2H_2O \rightarrow O_2 + 2H_2 \]
- **Match:** This corresponds to (T).

### Final Matches:
- A (KCl) → Q (H₂ discharged)
- B (H₂SO₄) → Q (H₂ discharged), R (O₂ discharged)
- C (CuSO₄) → P (Metal discharged at cathode), R (O₂ discharged)
- D (NaNO₃) → Q (H₂ discharged), R (O₂ discharged)
- T → Net cell reaction: \(2H_2O \rightarrow O_2 + 2H_2\)

### Summary of Matches:
- A → Q
- B → Q, R
- C → P, R
- D → Q, R
- T → Net cell reaction