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Figure shows graph of deviation delta ve...

Figure shows graph of deviation `delta` versus angle of incidence for a light ray striking a prism. Angle of prism is

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`75^(@)`

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The correct Answer is:
B
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From the graph fo angle of deviation delta versus angle of incidwence i . Find the prism angle

The graph between angle of deviation (delta) and angle of incidence (i) for a triangular prism is represented by

(i) Plot a graph to show variation of the angle of deviation as function of angle of incidence for light passing through a prism. Derive an expression for refractive index of the prism in terms of angle of minimum deviation and angles of prism. (ii) What is dispersion of light ? Why is its cause ? (iii) A ray of light incident normally on one face of a right isosceles prism is totally reflected as shown in fig . what must be the minimum value of refractive index of glass ? Give relevant calculations

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The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are :

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A plot between the angle of deviation and angle of incidence is shown in figure. From the graph one can say that the prism angle is

The figure shows a constant deviation prism ABCD. The incident ray is PQ and the emergent ray is ST. Although it is made up of one piece of glass, but it is equivalent to two 30^(@)-60^(@)-90^(@) prism and one 45^(@)-45^(@)90^(@) prism.The angle theta_(1) is the angle of incidence on face AB. The path of the ray inside the prism is indicated in the figure. for this prism mu=2sintheta_(1) . Q. The total deviation of incident ray when it emerges out of the prism is

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