A uniform ring of mass m and radius R is performing pure rolling motion on a horizontal surface. The velocity of centre of the ring is `V_(0)`. If at the given instant the kinetic energy of the semi circular are AOB is lambda `mv_(0)_(2)`, then find the value of `11lambda ("take" pi=(22)/(7))`

An object of mass M and radius R is performing pure rolling motion on a smooth horizontal surface under the action of a constant force F as shown in Fig. The object may be

A thin ring of mass m and radius R is in pure rolling over a horizontal surface. If v_0 is the velocity of the centre of mass of the ring, then the angular momentum of the ring about the point of contact is

A cycle tyre of mass M and radius R is in pure rolling over a horizontal surface. If the velocity of the centre of mass of the tyre is v, then the velocity of point P on the tyre, shown in figure is

A uniform thin ring of mass 0.4kg rolls without slipping on a horizontal surface with a linear velocity of 10 cm/s. The kinetic energy of the ring is

A disc is in the condition of pure rolling on the horizontal surface. The velocity of center of mass is V_0 If radius of disc is R then the speed of point P is (OP =R/3)

A uniform ring of radius R is given a back spin of angular velocity V_(0)//2R and thrown on a horizontal rough surface with velocity of centre to be V_(0) . The velocity of the centre of the ring when it starts pure rolling will be

A disc of mass 4 kg and of radius 1 m rolls on a horizontal surface without slipping such that the velocity of its centre of mass is 10" cm sec"^(-1) , Its rotatonal kinetic energy is

A disc shaped body (having a hole shown in the figure) of mass m=10kg and radius R=10/9m is performing pure rolling motion on a rough horizontal surface. In the figure point O is geometrical center of the disc and at this instant the centre of mass C of the disc is at same horizontal level with O . The radius of gyration of the disc about an axis pasing through C and perpendicular to the plane of the disc is R/2 and at the insant shown the angular velocity of the disc is omega=sqrt(g/R) rad/sec in clockwise sence. g is gravitation acceleration =10m//s^(2) . Find angular acceleation alpha ( in rad//s^(2) ) of the disc at this instant.

A ring mass m and radius R has three particle attached to the ring as shown in the figure. The centre of the centre v_(0) . Find the kinetic energy of the system. (Slipping is absent). .

A solid sphere is thrown on a horizontal rough surface with initial velocity of centre of mass V_0 without rolling. Velocity of its centre of mass when its starts pure rolling is