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The average value of altermating current...

The average value of altermating current `I=I_(0)sin omegat` in time interval `[0,(pi)/(omega)]` is

A

`(2I_(0))/pi`

B

`2I_(0)`

C

`(4I_(0))/pi`

D

`I_(0)/pi`

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(av)=(underset(0)overset(pi//omega)intIdt)/(pi/omega-0)=omega/piunderset(0)overset(pi//omega)intI_(0) sin omegatdt=omega/pi[(I_(0)(-cos omegat))/omega]_(0)^(pi//omega)=-omega/piI_(0)/omega[cos pi-cos 0]=-I_(0)/pi[-1-1]=(2I_(0))/pi`
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