The force of repulsion between two point charges is F, when these are at a distance of `1 m`. Now the point charges are replaced by spheres of radii `25 cm` having the charge same as that of point charges. The distance between their centres is `1 m`, then compare the force of repulsion in two cases.

Explanation

To solve the problem, we need to compare the force of repulsion between two point charges and the force of repulsion between two charged spheres of the same charge and radius. We will use Coulomb's law for both cases.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- The force of repulsion between two point charges (let's call them \( Q_1 \) and \( Q_2 \)) is \( F \) when they are \( 1 \, m \) apart.
- The distance between the centers of the two spheres is also \( 1 \, m \).
- The radius of each sphere is \( 25 \, cm \) (which is \( 0.25 \, m \)).
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