`1 mu C` charge is shifted from A to B and it is found that work done by external force is `80 mu J` against electrostic forces, find `V_(A)-V_(B)`

Explanation

To solve the problem, we need to find the difference in electric potential between points A and B, denoted as \( V_A - V_B \). We know that the work done by an external force in moving a charge in an electric field is related to the potential difference between two points.

### Step-by-step Solution:

1. **Identify the given values**:
- Charge \( q = 1 \, \mu C = 1 \times 10^{-6} \, C \)
- Work done \( W = 80 \, \mu J = 80 \times 10^{-6} \, J \)

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