A short electric dipole is situated at the origin of coordinate axis with its axis along x-axis and equator along y-axis. It is found that the magnitudes of the electric intensity and electric potential due to the dipole are equal at a point distance `r=sqrt(5) m` from origin. Find the position vector of the point in first quadrant.

Explanation

To solve the problem, we need to find the position vector of a point in the first quadrant where the magnitudes of the electric intensity and electric potential due to a short electric dipole are equal. The dipole is situated at the origin, with its axis along the x-axis.

### Step-by-Step Solution:

1. **Understanding the Electric Dipole**:
- A short electric dipole consists of two equal and opposite charges separated by a small distance. The dipole moment \( p \) is given by \( p = q \cdot d \), where \( q \) is the charge and \( d \) is the separation distance.

2. **Electric Field Intensity (E)**:
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