An electric field is given by `E=(y hat(i)+ xhat(k))N//C`. Work done in moving a 1C charge from `r_(A)=(2hat(i)+2hat(j))m` to `r_(B)=(4hat(i)+hat(j))m` is

Answer

0

Explanation

`A=(2, 2)` and `B=(4, 1), W_(A to B)=q(V_(B)-V_(A))=q underset(A)overset(B)(int)dV=- underset(A)overset(B)(int)qvec(E).dvec(r)`
`=qunderset(A)overset(B)(int)("yhat(i)+xhat(j)).(dxhat(i)+dyhat(j))=qunderset(A)overset(B)int(ydx+xdy)=-q underset("(2, 2)")overset("(4, 1)")(int)d(xy)=-q[xy]_("(2,2)")^("(4, 1)")=-q[4-4]=0`