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Let A=hatiA cos theta+hatj A sin theta b...

Let `A=hatiA cos theta+hatj A sin theta` be any vector .Another vector B which is perpendiculaar to A can be expressed as

A

`hat(i)B cos theta + hat(j)B sin theta`

B

`hat(i)B sin theta + hat(j)B cos theta`

C

`hat(i)B sin theta - hat(j)B cos theta`

D

`hat(i)A cos theta + hat(j)A sin theta`

Text Solution

Verified by Experts

The correct Answer is:
C
Check `vec(A).vec(B)=0`
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