`{:(,"Column I",,"Column II"),((A),"Dimensional variable",(p),pi),((B),"Dimensionless variable",(q),"Force"),((C),"Dimensional constant",(r),"Angle"),((D),"Dimensionless constant",(s),"Gravitational constant"):}`

Answer

To solve the problem of matching the items in Column I with those in Column II, we will analyze each item based on its dimensional properties.

### Step-by-Step Solution:

1. **Identify the nature of each item in Column I:**
- A: Dimensional variable
- B: Dimensionless variable
- C: Dimensional constant
- D: Dimensionless constant

2. **Analyze the items in Column II:**
- p: π (pi)
- q: Force
- r: Angle
- s: Gravitational constant

3. **Match each item:**
- **For p (π):**
- The dimensional formula for π is \( m^0 l^0 t^0 \), which means it has no dimensions. Therefore, π is a dimensionless constant.
- **Match:** D (Dimensionless constant) with p (π).

- **For q (Force):**
- The dimensional formula for force is \( m^1 l^1 t^{-2} \). This shows that force has dimensions.
- **Match:** A (Dimensional variable) with q (Force).

- **For r (Angle):**
- The dimensional formula for angle is also \( m^0 l^0 t^0 \), indicating that angle is dimensionless.
- **Match:** B (Dimensionless variable) with r (Angle).

- **For s (Gravitational constant):**
- The dimensional formula for the gravitational constant is \( m^1 l^3 t^{-2} \). This indicates that it has dimensions and is a constant.
- **Match:** C (Dimensional constant) with s (Gravitational constant).

4. **Final Matches:**
- A → q (Force)
- B → r (Angle)
- C → s (Gravitational constant)
- D → p (π)

### Summary of Matches:
- A (Dimensional variable) → q (Force)
- B (Dimensionless variable) → r (Angle)
- C (Dimensional constant) → s (Gravitational constant)
- D (Dimensionless constant) → p (π)