The position `x` of a particle at time `t` is given by `x = (V_(0))/(a) (1 - e^(-at))` , where `V_(0)` is constant and `a gt 0`. The dimensions of `V_(0)` and a are

Answer

`[v_(0)]=[m^(0)L^(1)T^(-1)][alpha]=[m^(0)L^(0)T^(-1)]`

Explanation

Dimension of `alpha t= M^(0)L^(0)T^(0)`
`rArr` Dimension of `alpha=M^(0)L^(0)T^(-1)`
Dimension of `v_(0)/alpha=L^(-1)`
`rArr` Dimension of `v_(0)=M^(0)L^(1)T^(-1)`