Home
Class 11
PHYSICS
Planck's constant has dimensions ……………....

Planck's constant has dimensions …………….

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensions of Planck's constant, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship**: We start with the formula relating energy (E), Planck's constant (h), and frequency (f): \[ E = h \cdot f \] 2. **Rearrange the formula**: To express Planck's constant in terms of energy and frequency, we rearrange the equation: \[ h = \frac{E}{f} \] 3. **Identify the dimensions**: Next, we need to find the dimensions of energy (E) and frequency (f): - The dimension of energy (E) is given by: \[ [E] = M L^2 T^{-2} \] - The dimension of frequency (f) is the reciprocal of time: \[ [f] = T^{-1} \] 4. **Substitute the dimensions**: Now we can substitute these dimensions into our expression for Planck's constant: \[ [h] = \frac{[E]}{[f]} = \frac{M L^2 T^{-2}}{T^{-1}} \] 5. **Simplify the expression**: When we divide by \(T^{-1}\), it is equivalent to multiplying by \(T^{1}\): \[ [h] = M L^2 T^{-2} \cdot T^{1} = M L^2 T^{-1} \] 6. **Final result**: Therefore, the dimensions of Planck's constant (h) are: \[ [h] = M L^2 T^{-1} \] ### Conclusion: The dimensions of Planck's constant are \(M L^2 T^{-1}\). ---

To find the dimensions of Planck's constant, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship**: We start with the formula relating energy (E), Planck's constant (h), and frequency (f): \[ E = h \cdot f \] ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise Exercise-02|77 Videos
  • MISCELLANEOUS

    ALLEN|Exercise Exercise-03|1 Videos
  • MISCELLANEOUS

    ALLEN|Exercise EXERCISE-5(A)|15 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

Dual nature of matter was proposed by de Broglie in 1923, it was experimentally verified by Davisson and Germer by diffraction experiment. Wave haracter of matter has significance only for microscopic particles. De Broglie wavelength (lambda) can be calculated using the relation, (lambda) = (h)/(m v) where 'm' and 'v' are the mass and velocity of the particle. Planck's constant has same dimension as that of

Gas constant 'R' has dimensions :

Photon is quantum of radiation with energy E =hv where v is frequency and h is Planck's constant. The dimensions of h are the same as that of

Boltzman's constant 'k' has dimensions of

Planck constant has the same dimensions as

Capacitance has dimensions :

E.M.F has dimensions of

The dimensions of Planck's constant is identical to

A quantity f is given by f=sqrt((hc^(5))/(G)) where c is speed of light, G universal gravitational constant and h is the Planck's constant. Dimension of f is that of:

In the ideal gas equation, the gas constant R has the dimension of -