In the formula `x=3yz^(2)`, x and y have dimensions of capacitance and magnetic induction respectively, then find the dimensions of y.

Answer

`[M^(-3)L^(-2)T^(4)Q^(4)]`

Explanation

`[X]=["capacitance"]=[M^(-1)L^(-2)Q^(2)]` and
`[Z]=["Magnetic induction"]=[MT^(-1)Q^(-1)]`
Therefore
`[Y]=([X])/([Z]^(2))=([M^(-1)L^(-2)T^(2)Q^(2)])/([MT^(-1)Q^(-1)]^(2))=[M^(-3)L^(-2)T^(4)Q^(4)]`