The dimensions of electrical conductivity are ……..

Answer

`[M^(-1)L^(-3)T^(3)A^(2)]`

Explanation

Electrical conductivity
`sigma=J/ErArr [sigma]=[(I//A)/(F//q)]=[(I//A)/(F//it)]=[(I^(2)t)/(FA)]`
`=[(A^(2)T)/((MLT^(-2))(L^(2)))]=[M^(-1)L^(-3)T^(3)A^(2)]`