Home
Class 11
PHYSICS
The dimensions of 1/2 epsilon(0)E^(2) (e...

The dimensions of `1/2 epsilon_(0)E^(2) (epsilon_(0)=` permittivity of free space, `E=` electric field) is

A

`[MLT^(-1)]`

B

`[ML^(2)T^(-2)]`

C

`[ML^(-1)T^(-2)]`

D

`[ML^(2)T^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`1/2 in_(0) E^(2)-[M^(-1)L^(-3)T^(4)I^(2)][M^(2)L^(2)T^(-6)I^(-2)]=[M^(1)L^(-1)T^(-2)]`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise Exercise-02|77 Videos

  • MISCELLANEOUS

    ALLEN|Exercise Exercise-03|1 Videos

  • MISCELLANEOUS

    ALLEN|Exercise EXERCISE-5(A)|15 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field

The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field

The dimensions of 1/2 in_(0) E^(2) ( in_(0) : permittivity of free space, E: electric field) is-

The dimensions of epsilon_(0)mu_(0) are

epsilon_(0)E^(2) has the dimensions of ( epsilon_(0)= permittivity of free space, E= electric field) Here k= Boltzmann consant T= absolute temperature R= universal gas constant.

The dimensions of (mu_(0)epsilon_(0))^(-1//2) are

The quantity X = (epsilon_(0)LV)/(t) where epsilon_(0) is the permittivity of free space, L is length, V is the potential difference and t is time. The dimensions of X are the same as that of

A wire of length L= 20 cm is bent into a semicircular arc and the two equal halves of the arc are uniformly charged with charges +Q and -Q as shown in the figure. The magnitude of the charge on each half is |Q| =10^(3) epsilon_(0) , where epsilon_(0) is the permittivity of free the space. The net electric field at the center O is

The unit of permittivity of free space epsilon_(0) is:

Which of the following does not have the dimensions of velocity ? ( Given epsilon_(0) is the permittivity of free space , mu_(0) is the permeability of free space , v is frequency , lambda is wavelength , P is the pressure , and rho is density , k is wave number , omega is the the angular frequency) (1) omega k (2) v lambda (3)1/ sqrt(epsilon_(0) mu_(0)) (4) sqrt(P/rho)

ALLEN-MISCELLANEOUS-Exersice -05(B)
  1. Planck's constant has dimensions …………….

    Text Solution

    |

  2. In the formula x=3yz^(2), x and y have dimensions of capacitance and m...

    Text Solution

    |

  3. The dimensions of electrical conductivity are ……..

    Text Solution

    |

  4. The equation of state of a real gas is given by (P+a/V^(2)) (V-b)=RT ...

    Text Solution

    |

  5. The dimensions of 1/2 epsilon(0)E^(2) (epsilon(0)= permittivity of fre...

    Text Solution

    |

  6. A quantity X is given by epsi(0)L(DeltaV)/(DeltaT) where epsi(0) is th...

    Text Solution

    |

  7. The relation p=(alpha)/(beta)e^((-alphaZ)/(ktheta) , where p is pressu...

    Text Solution

    |

  8. Which of the following sets have different dimensions ?

    Text Solution

    |

  9. L,C, and R represent the physical quantities inductance, capacitance a...

    Text Solution

    |

  10. The dimensions of the quantities in one ( or more) of the following pa...

    Text Solution

    |

  11. The pairs of physical quantities that have the same dimensions is (are...

    Text Solution

    |

  12. Let varepsilon(0) denote the permittivity of the vacuum and mu(0) that...

    Text Solution

    |

  13. The SI unit of inductance, the henry, can be written as

    Text Solution

    |

  14. Column-1 gives three physical quantities. Select the appropriate units...

    Text Solution

    |

  15. Match the physical quantities given in column I with dimensions expres...

    Text Solution

    |

  16. Ratio of amplitude for two wave is 15:9.Find the ratio of intensity?

    Text Solution

    |

  17. Match List I with List II and select the correct answer using the code...

    Text Solution

    |

  18. During Searle's experiment zero of the Vernieer scale lies between 3.2...

    Text Solution

    |

  19. To find the distance d over which a signal can be seen clearly in fogg...

    Text Solution

    |