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The are AB with the centre C and infinitely long wire having linear charge density `lambda` are lying in the same plane. The minium amount of work to be done to move a point charge `q_(0)` from point A to B through a circular path AB of radius a is equal to

A

`(q_(0)lambda)/(2pi in_(0))ln 3/2`

B

`(q_(0)lambda)/(4pi in_(0))ln 2`

C

`(q_(0)lambda)/(pi in_(0))ln 3/2`

D

`(q_(0) lambda)/(2pi in_(0))`

Text Solution

Verified by Experts

The correct Answer is:
C

`W_("ext")=-(Klambda)/(r) underset(r_(A))overset(r_(B))(int) r_(B)/r_(A)`
`W_("ext")=-K lambda ln r_(B)/r_(A)`
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