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A charge +q is placed at the origin O of...

A charge +q is placed at the origin O of x-y axes as shoen in the figure. The work done in taking a charge Q from A to B along the straight line AB is

A

`((-qQ)/(4pi in_(0))1/a^(2)) sqrt(2)a`

B

zero

C

`((qQ)/(4pi in_(0))1/a^(2)) 1/sqrt(2)a`

D

`((qQ)/(4pi in_(0))1/a^(2)) sqrt(2)a`

Text Solution

Verified by Experts

The correct Answer is:
B

Charge moves `bot^(r)` to the field lines. So the work done will be zero.
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