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A cavity of radius r is made inside a so...

A cavity of radius r is made inside a solid sphere. The volume charge density of the remaining sphere is p An electron (charge e, mass m) is released inside the cavity from point P as shown in figure. The centre of sphere and centre of cavity are separated by a distance a. The time after which the electron again touches the sphere is ` sqrt((sqrt(n) xepsi_(0)m)/(e0a)) ` find n.

Text Solution

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The correct Answer is:
`sqrt((6sqrt(2)mr in_(0))/(e rho a))`
The direction of electric field inside the cavity in -ve x direction and of constant magnitude `(rho a)/(3 in_(0))`

For touch the sphere again, electron must move `2r cos 45^(@)` (as shown) distance
`:. 1/2 [(rho a)/(3 in_(0))xxe/m]xxt^(2)=sqrt(2)r :. t=sqrt((6sqrt(2)mr in_(0))/(e rho a))`
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