`vec(a)=5` units due South West
`vec(b)=5` units due `53^(@)` North of East.
`vec(c)=10` units due `37^@` South of East.
Then which of the following is incorrect.
`vec(a)=5` units due South West
`vec(b)=5` units due `53^(@)` North of East.
`vec(c)=10` units due `37^@` South of East.
Then which of the following is incorrect.
`vec(b)=5` units due `53^(@)` North of East.
`vec(c)=10` units due `37^@` South of East.
Then which of the following is incorrect.
A
`vec(a)+vec(b)=-2hat(i)-hat(j)`
B
`vec(a).vec(b)=-(35)/(sqrt2)`
C
`vec(b).vec(c)=0`
D
`vec(b)+vec(c)=11hat(i)-2hat(j)`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we will analyze the vectors given and compute their components. We will then check the correctness of the statements regarding these vectors.
### Step-by-Step Solution:
1. **Identify the vectors**:
- Vector \( \vec{a} = 5 \) units due South West.
- Vector \( \vec{b} = 5 \) units due \( 53^\circ \) North of East.
- Vector \( \vec{c} = 10 \) units due \( 37^\circ \) South of East.
2. **Convert vector \( \vec{a} \) to components**:
- Since South West is at an angle of \( 45^\circ \) from both South and West, we can express \( \vec{a} \) in terms of its components:
\[
\vec{a} = 5 \cos(225^\circ) \hat{i} + 5 \sin(225^\circ) \hat{j}
\]
- Using \( \cos(225^\circ) = -\frac{1}{\sqrt{2}} \) and \( \sin(225^\circ) = -\frac{1}{\sqrt{2}} \):
\[
\vec{a} = 5 \left(-\frac{1}{\sqrt{2}}\right) \hat{i} + 5 \left(-\frac{1}{\sqrt{2}}\right) \hat{j} = -\frac{5}{\sqrt{2}} \hat{i} - \frac{5}{\sqrt{2}} \hat{j}
\]
3. **Convert vector \( \vec{b} \) to components**:
- For \( \vec{b} \) which is \( 53^\circ \) North of East:
\[
\vec{b} = 5 \cos(53^\circ) \hat{i} + 5 \sin(53^\circ) \hat{j}
\]
- Using \( \cos(53^\circ) \approx 0.6 \) and \( \sin(53^\circ) \approx 0.8 \):
\[
\vec{b} \approx 5(0.6) \hat{i} + 5(0.8) \hat{j} = 3 \hat{i} + 4 \hat{j}
\]
4. **Convert vector \( \vec{c} \) to components**:
- For \( \vec{c} \) which is \( 37^\circ \) South of East:
\[
\vec{c} = 10 \cos(37^\circ) \hat{i} - 10 \sin(37^\circ) \hat{j}
\]
- Using \( \cos(37^\circ) \approx 0.8 \) and \( \sin(37^\circ) \approx 0.6 \):
\[
\vec{c} = 10(0.8) \hat{i} - 10(0.6) \hat{j} = 8 \hat{i} - 6 \hat{j}
\]
5. **Calculate \( \vec{a} + \vec{b} \)**:
\[
\vec{a} + \vec{b} = \left(-\frac{5}{\sqrt{2}} + 3\right) \hat{i} + \left(-\frac{5}{\sqrt{2}} + 4\right) \hat{j}
\]
6. **Calculate \( \vec{b} + \vec{c} \)**:
\[
\vec{b} + \vec{c} = (3 + 8) \hat{i} + (4 - 6) \hat{j} = 11 \hat{i} - 2 \hat{j}
\]
7. **Calculate dot products**:
- \( \vec{a} \cdot \vec{b} = \left(-\frac{5}{\sqrt{2}} \cdot 3\right) + \left(-\frac{5}{\sqrt{2}} \cdot 4\right) = -\frac{15}{\sqrt{2}} - \frac{20}{\sqrt{2}} = -\frac{35}{\sqrt{2}} \)
- \( \vec{b} \cdot \vec{c} = (3 \cdot 8) + (4 \cdot -6) = 24 - 24 = 0 \)
8. **Determine which statement is incorrect**:
- After calculating the vectors and their operations, we can conclude which option is incorrect based on the results obtained.
### Conclusion:
The incorrect statement is related to the calculations of the vectors or their resultant operations.
To solve the problem, we will analyze the vectors given and compute their components. We will then check the correctness of the statements regarding these vectors.
### Step-by-Step Solution:
1. **Identify the vectors**:
- Vector \( \vec{a} = 5 \) units due South West.
- Vector \( \vec{b} = 5 \) units due \( 53^\circ \) North of East.
- Vector \( \vec{c} = 10 \) units due \( 37^\circ \) South of East.
...
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