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Which relation is incorrect about hydrol...

Which relation is incorrect about hydrolysis of WASB salt ?

A

`[H^(+)]=sqrt((K_(w)xxK_(a))/(c)`

B

`pOH=1/2(pk_(w)-pK_(a)-logC)`

C

`[OH^(-)]=sqrt((K_(w)xxC)/(K_(a))`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question "Which relation is incorrect about the hydrolysis of WASB (Weak Acid Strong Base) salt?", we need to analyze the hydrolysis process and the relationships involved. ### Step-by-Step Solution: 1. **Understanding Hydrolysis of WASB Salt**: - A salt formed from a weak acid (HA) and a strong base (BOH) undergoes hydrolysis in water. The salt dissociates into its ions: \( B^+ \) (from the strong base) and \( A^- \) (from the weak acid). 2. **Dissociation Reaction**: - The dissociation of the salt in water can be represented as: \[ BA \rightarrow B^+ + A^- \] - The \( A^- \) ions can react with water (hydrolysis) to form \( OH^- \) and \( HA \): \[ A^- + H_2O \rightleftharpoons HA + OH^- \] 3. **Hydrolysis Constant (K_h)**: - The hydrolysis constant \( K_h \) can be expressed as: \[ K_h = \frac{[OH^-][HA]}{[A^-]} \] 4. **Dissociation Constant of Weak Acid (K_a)**: - The dissociation constant for the weak acid \( HA \) is given by: \[ K_a = \frac{[H^+][A^-]}{[HA]} \] 5. **Ionic Product of Water (K_w)**: - The relationship between \( K_w \), \( K_a \), and \( K_h \) is given by: \[ K_h \cdot K_a = K_w \] - This implies: \[ K_h = \frac{K_w}{K_a} \] 6. **Degree of Hydrolysis (H)**: - The degree of hydrolysis \( H \) can be expressed in terms of concentration \( C \) and \( K_h \): \[ H = \sqrt{\frac{K_h}{C}} \] - Substituting \( K_h \) gives: \[ H = \sqrt{\frac{K_w}{K_a \cdot C}} \] 7. **pH and pOH Relationships**: - The pH can be calculated from the concentration of \( H^+ \): \[ pH = -\log[H^+] \] - The relationship between pH and pOH is: \[ pH + pOH = 14 \] 8. **Identifying Incorrect Relations**: - Based on the derived relationships, we need to evaluate the options provided in the question to identify any incorrect relations. - If none of the relations contradict the established formulas and relationships above, then the answer would be that none of the relations are incorrect. ### Conclusion: After analyzing the hydrolysis of the weak acid strong base salt and deriving the relevant equations, we conclude that none of the relations provided in the question are incorrect.

To solve the question "Which relation is incorrect about the hydrolysis of WASB (Weak Acid Strong Base) salt?", we need to analyze the hydrolysis process and the relationships involved. ### Step-by-Step Solution: 1. **Understanding Hydrolysis of WASB Salt**: - A salt formed from a weak acid (HA) and a strong base (BOH) undergoes hydrolysis in water. The salt dissociates into its ions: \( B^+ \) (from the strong base) and \( A^- \) (from the weak acid). 2. **Dissociation Reaction**: ...
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ALLEN-TEST PAPER-Exercise (Chemstry)
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