Home
Class 12
CHEMISTRY
The densities of graphite and diamond at...

The densities of graphite and diamond at 298 K are 2.25 and 3.31 g `cm^(-3)` , respectively . If the standard free energy difference `(DeltaG^(@))` is equal to 1895 J `"mol"^(-1)` , the pressure at which graphite will be transformed into diamond at 298 K is

A

`7.92xx10^(8) Pa`

B

`9.92xx10^(9) Pa`

C

`9.92xx10^(10) Pa`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

`N//A`
Promotional Banner

Topper's Solved these Questions

  • TEST PAPER

    ALLEN|Exercise Exercise (Chemistry)|161 Videos
  • TEST PAPER

    ALLEN|Exercise Exercise (Chemstry)|26 Videos
  • SURFACE CHEMISTRY

    ALLEN|Exercise ASSERTION & REASO|20 Videos
  • TEST PAPER 1

    ALLEN|Exercise CHEMISTRY|11 Videos

Similar Questions

Explore conceptually related problems

The densities of graphite and diamond at 298K are 2.25 and 3.31gcm^(-3) , respectively. If the standard free energy difference (DeltaG^(0)) is equal to 1895Jmol^(-1) , the pressure at which graphite will be transformed into diamond at 298K is

The bond energies of C=C and C-C at 298 K are 590 and 331 kJ mol^(-1) , respectively. The enthalpy of polymerisation per mole of ethaylene is

The densities of graphite and diamond are 22.5 and 3.51 gm cm^(-3) . The Delta_(f)G^(ɵ) values are 0 J mol^(-1) and 2900 J mol^(-1) for graphite and diamond, respectively. Calculate the equilibrium pressure for the conversion of graphite into diamond at 298 K .

Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

Densities of diamond and graphite are 3 and 2 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

The standard enthalpy of diamond is zero at 298K and 1 atm pressure.

The standard free energy of formation of NO(g) is 86.6 kJ/ mol at 298 K what is the standard free energy of formation of NO_(2) g at 298 k? K _(p)= 1.6 xx 10^(12)

The standard state Gibbs free energies of formation of ) C(graphite and C(diamond) at T = 298 K are Delta_(f)G^(@)["C(graphite")]=0kJ mol^(-1) Delta_(f)G^(@)["C(diamond")]=2.9kJ mol^(-1) The standard state means that the pressure should be 1 bar, and substance should be pure at a given temperature. The conversion of graphite [ ) C(graphite ] to diamond [C(diamond)] reduces its volume by 2xx10^(-6)m^(3) mol^(-1). If ) C(graphite is converted to C(diamond) isothermally at T = 298 K, the pressure at which ) C(graphite is in equilibrium with C(diamond), is ["Useful information:"1J=1kg m^(2)s^(-2),1Pa=1kgm^(-1)s^(-2),1"bar"=10^(5)Pa]

Standard enthalpy and standard entropy change for the oxidation of NH_(3) at 298K are -382.64KJ mol^(-1) and 145.6Jmol^(-1) respectively. Standard free energy change for the same reaction at 298K is

The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are, -890.3 kJ mol^(-1) -393.5 kJ mol^(-1) , and -285.8 kJ mol^(-1) respectively. Enthapy of formation of CH_(4)(g) will be

ALLEN-TEST PAPER-Exercise (Chemstry)
  1. The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm^...

    Text Solution

    |

  2. Assertion (A): The enthalpy of formation of H(2)O(l) is greater than t...

    Text Solution

    |

  3. Assertion :- The molarity of a certain solution is always greater than...

    Text Solution

    |

  4. Assertion :- K(c) for process 2H(2)O(l)hArr2H(2)O((g))+O(2(g))may be w...

    Text Solution

    |

  5. Assertion :- Adding inert gas at equilibrium to dissociation of PCl(...

    Text Solution

    |

  6. Assertion (A) At constant temperature, pV vs V plot for real gases is ...

    Text Solution

    |

  7. Assertion :- Change in internal energy is zero for all gases at consta...

    Text Solution

    |

  8. Assertion :- Following amide exist in two structural forms. Reaso...

    Text Solution

    |

  9. Assertion :- Benzaldehyde forms two oximes on reaction with NH(2)OH. ...

    Text Solution

    |

  10. Assertion : -I effect of Cl atom is greater than F atom. Reason : Cl...

    Text Solution

    |

  11. Assertion: Cyclobutane is less stable than cyclopentane Reason : T...

    Text Solution

    |

  12. Assertion : The IUPAC name for the compound C(6)H(5)COOCH(2)CH(2)COOH ...

    Text Solution

    |

  13. Assertion :- The IUPAC name for the compound is 7-oxabicyclo [4,1,3] ...

    Text Solution

    |

  14. Assertion :- The IUPAC name of the compound is cyclohexylidene methan...

    Text Solution

    |

  15. Assertion (A) Electron gain enthalpy becomes less negative as we go do...

    Text Solution

    |

  16. Why does the reaction. proceed better with KF than with NaF ?

    Text Solution

    |

  17. Assertion :- Fire in reaction between saline hydride and water can ...

    Text Solution

    |

  18. Assertion :- BaSO(4) forms white ppt in water. Reason :- Its lattice...

    Text Solution

    |

  19. Assertion (A) SF(6) cannot be hydrolysed but SF(4) can be. Reason...

    Text Solution

    |

  20. A:Mn(2)O(7), is acidic in nature R: My has +7 oxidation state:

    Text Solution

    |

  21. Assertion (A) : Silicones are water repelling in nature Reason (R) :...

    Text Solution

    |